Grade 5 Multiplying and Dividing Fractions Review Answers Ida

Fractions Worksheets Class 5 contains xiv MCQ questions. Answers to Fractions Worksheets Grade 5 are available after clicking on the respond. Maths Worksheets for Class 5 help to check the concept yous have learnt from detailed classroom sessions and application of your noesis.

Fractions Worksheets Grade 5

Q.1) Compare $\cfrac{11}{3}$ and $\cfrac{5}{3}$
a) $\cfrac{11}{3}$ < $\cfrac{5}{3}$
b) $\cfrac{11}{3}$ > $\cfrac{5}{3}$

Answer

Answer: b) $\cfrac{11}{3}$ > $\cfrac{5}{3}$

Explanation
On Cross Multiplication $\cfrac{11}{3}$ and $\cfrac{5}{3}$
We multiply 11 ten 3 = 33
Similarly, nosotros multiply 3 10 5 = 15
The Fraction whose Numerator has higher value, after multiplication, is greater Fraction
Since, 33 > xv
Hence, $\cfrac{11}{3}$ > $\cfrac{5}{3}$

Q.two) Convert $\cfrac{59}{10}$ into Mixed Fraction.
a) $5\cfrac{5}{10}$
b) $5\cfrac{7}{10}$
c) $5\cfrac{9}{10}$

Respond

Answer: c) $5\cfrac{9}{10}$

Explanation
On dividing 59 past 10
We get, Quotient = 5
Remainder = 9
For a mixed Fraction we have to write Caliber + $\cfrac { Remainder }{ Divisor }$
So, the mixed Fraction is v + $\cfrac{9}{10}$ = $5\cfrac{9}{10}$

Q.3) Catechumen the Fraction $3\cfrac { 2 }{ 3 }$ into an Improper Fraction
a) $\cfrac { 11 }{ 3 }$
b) $\cfrac { 12 }{ 3 }$
c) $\cfrac { 13 }{ 3 }$

Answer: a) $\cfrac { 11 }{ 3 }$

Explanation
A combination of Whole Number and a Proper Fraction is called a Mixed Fraction
Hither, Mixed Fraction = $3\cfrac { 2 }{ 3 }$
Whole Number Part = three
Numerator = 2
Denominator = iii
Footstep 1 : Multiply the Whole Number Part and Denominator of the Mixed Fraction
3 x 3 = 9
Step 2 : Add the Numerator to the production obtained in Step i
2 + 9 = xi
Write the sum equally the numerator and denominator would remain the same , as in the Mixed Fraction.
$\cfrac { 11 }{ 3 }$
Hence, $3\cfrac { 2 }{ 3 }$ = $\cfrac { 11 }{ 3 }$

Q.4) Solve $\cfrac{5}{12}$ ÷ $\cfrac{25}{6}$
a) $\cfrac{10}{3}$
b) $\cfrac{3}{10}$
c) $\cfrac{1}{10}$

Answer

Answer: c) $\cfrac{1}{10}$

Explanation
$\cfrac{5}{12}$ ÷ $\cfrac{25}{6}$
In social club to Divide i fraction by another, we tin multiply the commencement Fraction with the reciprocal of the second Fraction
Reciprocal of second Fraction $\cfrac{25}{6}$ is $\cfrac{6}{25}$
or nosotros tin say $\cfrac{5}{12}$ ten $\cfrac{6}{25}$
Now, on simplifying it
= $\cfrac{1}{2}$ x $\cfrac{1}{5}$
Multiply all the Numerator together and all the Denominator together.
= $\cfrac{1}{10}$

Q.v) Notice three Fractions Equivalent to $\cfrac{11}{6}$ ?
a) $\cfrac{25}{12}$ , $\cfrac{31}{18}$ , $\cfrac{49}{24}$
b) $\cfrac{44}{9}$ , $\cfrac{35}{16}$ , $\cfrac{43}{24}$
c) $\cfrac{22}{12}$ , $\cfrac{33}{18}$ , $\cfrac{44}{24}$

Answer

Answer: c) $\cfrac{22}{12}$ , $\cfrac{33}{18}$ , $\cfrac{44}{24}$

Caption
To get a Fraction equivalent to a given Fraction, we multiply or carve up the Numerator and the Denominator of the given Fraction by the same number (except 0 or 1)
Fraction one : $\cfrac { 11\times 2 }{6\times 2}$ = $\cfrac{22}{12}$
Fraction 2 : $\cfrac { 11\times 3 }{6\times 3}$ = $\cfrac{33}{18}$
Fraction iii : $\cfrac { 11\times 4 }{6\times 4}$ = $\cfrac{44}{24}$
Hence, three Equivalent Fractions of $\cfrac{11}{6}$ are $\cfrac{22}{12}$ , $\cfrac{33}{18}$ , $\cfrac{44}{24}$

Q.6) If $\cfrac{20}{23}$ = $\cfrac{y}{46}$ , So the value of y is ___
a) forty
b) 43
c) 36

Answer

Answer: a) 40

Explanation
Given : $\cfrac{20}{23}$ = $\cfrac{y}{46}$
On Cross multiplication, nosotros get
20 x 46 = y 10 23
920 = 23y
$\cfrac{920}{23}$ = y
xl = y
Or, y = forty
Hence, the missing number is = 40

Fractions Worksheets Class 5

Q.7) Find : $\cfrac{15}{7}$ x $\cfrac{21}{60}$
a) $\cfrac{5}{4}$
b) $\cfrac{3}{4}$
c) $\cfrac{6}{5}$

Respond

Answer: b) $\cfrac{3}{4}$

Explanation
$\cfrac{15}{7}$ x $\cfrac{21}{60}$
To reduce the fraction into its simplest form, we accept the HCF of Numerator and Denominator i.e
$\cfrac{1}{1}$ 10 $\cfrac{3}{4}$
fifteen and 60 are divided past the common cistron 15 and the Numerator 21 and Denominator 7 are divided by common factor vii .
The remaining Numerator 3 and the Denominator 4 do not accept a common factor and cannot be simplified. then, multiply all the Numerator together and all the Denominator together.
We get, $\cfrac{3}{4}$

Q.8) Write downwardly the Numerator and Denominator of the Fraction: $\cfrac{14}{11}$
a) Numerator 14 , Denominator xi
b) Numerator xi , Denominator 14

Answer

Respond: a) Numerator xiv , Denominator 11

Explanation
Numerator is the Upper Number , in the Fraction
Then, the Numerator of $\cfrac{14}{11}$ is 14
Denominator is the bottom number in the Fraction
So, the Denominator of $\cfrac{14}{11}$ is 11

Q.ix) In a class of 60 children, $\cfrac{5}{6}$ are boys. How many boys and girls are there in the form?
a) Number of boys = 45 , Number of girls = 15
b) Number of boys = 50 , Number of girls = 10
c) Number of boys = 55 , Number of girls = five

Answer

Answer: b) Number of boys = 50 , Number of girls = 10

Explanation
Total number of children in the grade = 60
It is given that,
$\cfrac{5}{6}$ of Full number of children in the class = Number of boys
Number of boys = $\cfrac{5}{6}$ x 60
On simplifying information technology
Number of boys = $\cfrac{5}{1}$ x 10
Number of boys = fifty
Number of girls = Total number of children in the course – Number of boys
Number of girls = 60 – l
Number of girls = ten

Q.10) A jar is $\cfrac{8}{15}$ total. The Fraction of the jar that is empty is ?
a) $\cfrac{7}{15}$
b) $\cfrac{8}{15}$
c) $\cfrac{9}{15}$

Answer

Answer: a) $\cfrac{7}{15}$

Caption
Part of jar which is full = $\cfrac{8}{15}$
Since, we don't know the total role , we assume it to be $\cfrac{1}{1}$ ( in Fraction )
The part of the bucket that is empty = Total part – Filled part
= $\cfrac{1}{1}$ – $\cfrac{8}{15}$
Taking the LCM of i and xv = 15
= $\cfrac { 1\times 15-8\times 1 }{ 15 }$
= $\cfrac{15 - 8}{15}$
= $\cfrac{7}{15}$
Hence, the empty part of the bucket = $\cfrac{7}{15}$

Q.eleven) Find the difference of $\cfrac{7}{3}$ – $\cfrac{2}{3}$ and reduce into its lowest term.
a) $\cfrac{5}{3}$
b) $\cfrac{4}{3}$

Answer

Answer: a) $\cfrac{5}{3}$

Explanation
Difference of Like Fraction = $\cfrac { Difference\quad of\quad their\quad Numerators }{ Common\quad Denominator }$
= $\cfrac{7-2}{3}$
= $\cfrac{5}{3}$
And then, the difference of $\cfrac{7}{3}$ and $\cfrac{2}{3}$ is $\cfrac{5}{3}$

Q.12) Find the departure of $\cfrac{7}{6}$ and $\cfrac{7}{12}$ and reduce to its lowest term.
a) $\cfrac{7}{12}$
b) $\cfrac{9}{12}$
c) $\cfrac{8}{12}$

Respond

Reply: a) $\cfrac{7}{12}$

Caption
To find the divergence of Different Fraction
Firstly, we have to modify the Unlike Fraction into equivalent Like Fraction, and and so subtract the ii equivalent Like Fraction
Have LCM of 6 and 12 is 12
Converting the Dissimilar Fraction into Equivalent Similar Fraction
Nosotros have to multiply Numerator and Denominator of $\cfrac{7}{6}$ by ii
$\cfrac { 7\times 2 }{6\times 2}$ = $\cfrac{14}{12}$
Nosotros accept to multiply Numerator and Denominator of $\cfrac{7}{12}$ past 1
$\cfrac { 7\times 1 }{12\times 1}$ = $\cfrac{7}{12}$
Now $\cfrac{14}{12}$ – $\cfrac{7}{12}$ = $\cfrac{7}{12}$
Hence, the answer is $\cfrac{7}{12}$

Q.13) Find the sum of $\cfrac{1}{15}$ and $\cfrac{8}{15}$ and reduce to its lowest term.
a) $\cfrac{5}{3}$
b) $\cfrac{4}{5}$
c) $\cfrac{3}{5}$

Answer

Answer: c) $\cfrac{3}{5}$

Explanation
Sum of Like Fraction = $\cfrac { Sum\quad of\quad their\quad Numerators }{ Common\quad Denominator }$
= $\cfrac{1+8}{15}$
= $\cfrac{9}{15}$
Hence, the sum of $\cfrac{1}{15}$ and $\cfrac{8}{15}$ is $\cfrac{9}{15}$
Simplifying further,
HCF of 9 and 15 is iii
Dividing both Numerator and Denominator by their HCF i.e,
$\cfrac{9 \div 3 }{15 \div 3 }$ = $\cfrac{3}{5}$
Hence, the sum of $\cfrac{1}{15}$ and $\cfrac{8}{15}$ = $\cfrac{3}{5}$

Q.14) Observe the sum of $\cfrac{2}{3}$ and $\cfrac{3}{2}$ and reduce to its everyman term.
a) $\cfrac{13}{6}$
b) $\cfrac{5}{6}$
c) $\cfrac{11}{6}$

Answer

Answer: a) $\cfrac{13}{6}$

Explanation
In order to add Unlike Fraction
Firstly, nosotros have to change the Unlike Fraction, into equivalent Like Fractions, and so add the two equivalent Similar Fractions
Accept LCM of 3 and 2 is 6
Converting the Unlike Fraction into Equivalent Similar Fraction
We have to multiply , both the numerator and denominator of $\cfrac{2}{3}$ by 2
$\cfrac { 2\times 2 }{3\times 2}$ = $\cfrac{4}{6}$
Similarly, we accept to multiply , both the numerator and denominator of $\cfrac{3}{2}$ by three
$\cfrac { 3\times 3 }{2\times 3}$ = $\cfrac{9}{6}$
Now $\cfrac{4}{6}$ + $\cfrac{9}{6}$ = $\cfrac{13}{6}$
Hence, the sum of $\cfrac{2}{3}$ and $\cfrac{3}{2}$ is $\cfrac{13}{6}$